When same quantity of electricity is passed through aqueous $\mathrm{AgNO}_3$ and $\mathrm{H}_2…
When same quantity of electricity is passed through aqueous $\mathrm{AgNO}_3$ and $\mathrm{H}_2 \mathrm{SO}_4$ solutions connected in series, $5.04 \times 10^{-2} \mathrm{~g}$ of $\mathrm{H}_2$ is liberated. What is the mass of silver (in grams) deposited ? (Eq. wts. of hydrogen $=1.008$, silver $=108)$
$54$
$0.54$
$0.5$
$10.8$
Solution
Given, weight of hydrogen liberated
$
=5.04 \times 10^{-2} \mathrm{~g}
$
Eq. wt. of hydrogen $=1.008$
Eq. wt. of silver $=108$
Weight of silver deposited, $w=$ ?
According to Faraday's second law of electrolysis
weight of silver deposited
weight of hydrogen liberated
$
\begin{aligned}
& =\frac{\text { eq. wt. of silver }}{\text { eq. wt. of hydrogen }} \\
\frac{w}{5.04 \times 10^{-2}} & =\frac{108}{1.008} \\
w=\frac{108 \times 5.04 \times 10^{-2}}{1.008} & =5.4 \mathrm{~g}
\end{aligned}
$