$\mathrm{AlI}_{3}$, when reacts with $\mathrm{CCl}_{4}$, gives

$\mathrm{AlI}_{3}$, when reacts with $\mathrm{CCl}_{4}$, gives
  1. $\mathrm{AlCl}_{3}$
  2. $\mathrm{CI}_{4}$
  3. $\mathrm{Al}_{4} \mathrm{C}_{3}$
  4. both (a) and (b)

Solution

$\mathrm{AlI}_{3}$, on reaction with $\mathrm{CCl}_{4}$, gives the $\mathrm{AlCl}_{3}$ $4 \mathrm{AlI}_{3}+3 \mathrm{CCl}_{4} \longrightarrow 4 \mathrm{AlCl}_{3}+3 \mathrm{CI}_{4}$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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