When phenol is treated with $\mathrm{CHCl}_3$ and $\mathrm{NaOH}$, the product formed is:

Question

Aicharya · Accepted Answer

When phenol is treated with $\mathrm{CHCl}_3$ and $\mathrm{NaOH}$ the product formed is salicylaldehyde, this reaction is known as Reimer-Tiemann reaction. In this reaction chloroform first reacts with sodium hydroxide toproduce dichlorocarbene which is the intermediate of this reaction.

When phenol is treated with $\mathrm{CHCl}_3$ and $\mathrm{NaOH}$, the product formed is:

Solution