When fused NaCl undergoes electrolysis the product formed at cathode is

When fused NaCl undergoes electrolysis the product formed at cathode is
  1. $\mathrm{Cl}_{2(\mathrm{~g})}$
  2. $\mathrm{Na}_{(\mathrm{s})}$
  3. $\mathrm{Na}-\mathrm{Hg}_{(1)}$
  4. $\mathrm{H}_{2(\mathrm{~g})}$

Solution

- Concept: Electrolysis of fused NaCl leads to the reduction of $\mathrm{Na}^{+}$ions at the cathode to form $N a(s)$.

Asked in: MHT CET 2024 (11 May Shift 1)

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