When forces $F_1, F_2, F_3$ are acting on a particle of mass $m$ such that $F_2$ and $F_3$ are mutually…

When forces $F_1, F_2, F_3$ are acting on a particle of mass $m$ such that $F_2$ and $F_3$ are mutually perpendicular, then the particle remains stationary. If the force $F_1$ is now removed then the acceleration of the particle is
  1. $\mathrm{F}_1 / \mathrm{m}$
  2. $\mathrm{F}_2 \mathrm{~F}_3 / \mathrm{mF}_1$
  3. $\left(F_2-F_3\right) / m$
  4. $\mathrm{F}_2 / \mathrm{m}$

Solution

Resultant of F2 and F3 is of magnitude F1.

Asked in: JEE Main 2002

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