When $1: 2$ equivalence ratio of the gases $X$ and $Y$ are heated to $573 \mathrm{~K}-673 \mathrm{~K}$ at…
When $1: 2$ equivalence ratio of the gases $X$ and $Y$ are heated to $573 \mathrm{~K}-673 \mathrm{~K}$ at $200-300$ atm in the presence of $\mathrm{ZnO}-\mathrm{Cr}_2 \mathrm{O}_3$ catalyst, methanol is formed. Here, the gases $X$ and $Y$ are and respectively.
$\mathrm{CO}_2$ and $\mathrm{H}_2$
$\mathrm{CO}$ and $\mathrm{H}_2$
$\mathrm{CH}_4$ and $\mathrm{O}_2$
$\mathrm{CH}_4$ and $\mathrm{H}_2 \mathrm{O}(g)$
Solution
$X+2 Y \xrightarrow[\mathrm{Cr}_2 \mathrm{O}_3]{\mathrm{ZnO}} \mathrm{CH}_3 \mathrm{OH}$
Methanol is prepared on an industrial scale from a mixture of $\mathrm{CO}$ and $\mathrm{H}_2$. The mixture is subjected to 200 atm pressure and passed over $\mathrm{ZnO}$ and $\mathrm{Cr}_2 \mathrm{O}_3$ catalyst at $400-450^{\circ} \mathrm{C}$
$\mathrm{CO}+2 \mathrm{H}_2 \xrightarrow[\mathrm{Cr}_2 \mathrm{O}_3]{\mathrm{ZnO}} \underset{\text { (Methanol) }}{\mathrm{CH}_3 \mathrm{OH}}$
So, $X=\mathrm{CO}$ and $Y=\mathrm{H}_2$