When chlorine reacts with hot and cone. NaOH , the products formed are
- $\mathrm{NaCl}, \mathrm{NaClO}_3, \mathrm{H}_2 \mathrm{O}$
- $\mathrm{NaCl}, \mathrm{NaOCl}, \mathrm{H}_2 \mathrm{O}$
- $\mathrm{NaCl}, \mathrm{H}_2 \mathrm{O}$ only
- $\mathrm{NaOCl}, \mathrm{H}_2 \mathrm{O}$
Solution
Asked in: AP EAMCET 2024 (18 May Shift 1)
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