When an electron is excited from its $4^{\text {th }}$ orbit $5^{\text {th }}$ stationary orbit, the change…

When an electron is excited from its $4^{\text {th }}$ orbit $5^{\text {th }}$ stationary orbit, the change in the angular momentum of electron is approximately (Plank's constant $=\mathrm{h}=6.63 \times 10^{-34} \mathrm{Js}$ )
  1. $2 \times 10^{-34} \mathrm{Js}$
  2. $6.63 \times 10^{-34} \mathrm{Js}$
  3. $1 \times 10^{-34} \mathrm{Js}$
  4. $3.14 \times 10^{-34} \mathrm{Js}$

Solution

Change in Angular Momentum: $\Delta \mathrm{L}=\mathrm{L}_2-\mathrm{L}_1$ $=\frac{\mathrm{n}_2 \mathrm{~h}}{2 \pi}-\frac{\mathrm{n}_1 \mathrm{~h}}{2 \pi}$ $=\frac{\mathrm{h}}{2 \pi}(5-4)$ $=\frac{6.63 \times 10^{-34} \mathrm{Js}}{2 \pi}$ $=1 \times 10^{-34} \mathrm{Js}$

Asked in: MHT CET 2023 (13 May Shift 2)

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