When $X$ amperes of current is passed through molten $\mathrm{AlCl}_3$ for $96.5 \mathrm{~s}, 0.09…
When $X$ amperes of current is passed through molten $\mathrm{AlCl}_3$ for $96.5 \mathrm{~s}, 0.09 \mathrm{~g}$ of aluminium is deposited. What is the value of $X$ ?
10 ampere
20 ampere
30 ampere
40 ampere
Solution
Current $i=$ ?
Equivalent weight of $\mathrm{Al}=\frac{27}{3}=9$
$w=z i t$
$i=\frac{w}{z t}=\frac{0.09 \times 96500}{9 \times 96.5}=10$ ampere