When acetylene is passed through red hot iron tube, compound $X$ is formed. Which one of the following…

When acetylene is passed through red hot iron tube, compound $X$ is formed. Which one of the following reactions will yield $X$ as the major product?
  1. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}+\mathrm{Zn} \stackrel{\text { Distillation }}{\longrightarrow}$
  2. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_3 \mathrm{H}+\mathrm{NaHCO}_3 \longrightarrow$
  3. $\mathrm{C}_6 \mathrm{H}_{12}+3 \mathrm{H}_2 \stackrel{\mathrm{Ni}}{\longrightarrow}$
  4. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{Cl}+\mathrm{H}_2 \mathrm{O} \stackrel{\Delta}{\longrightarrow}$

Solution

When acetylene is passed through red hot iron tube, benzene is formed as $3 \mathrm{C}_2 \mathrm{H}_2 \stackrel{\text { red hot tube }}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_6$(X)$ Reaction (a) also gives $\mathrm{C}_6 \mathrm{H}_6$ (or $X$ ) as $\mathrm{C}_6 \mathrm{H}_5 \mathrm{OH}+\mathrm{Zn} \stackrel{\text { distillation }}{\longrightarrow} \mathrm{C}_6 \mathrm{H}_6+\mathrm{ZnO}$

Asked in: AP EAMCET 2003

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