When a wire of uniform cross section $a$, length $l$ and resistance $R$ is into a complete circle,…
- $\frac{R}{4}$
- $4 R$
- $\frac{R}{8}$
- $\frac{R}{2}$
Solution
$\begin{aligned}
& \frac{1}{R^{\prime}}=\frac{2}{R}+\frac{2}{R}=\frac{4}{R} \\
& \Rightarrow \quad R^{\prime}=\frac{R}{4}
\end{aligned}$Asked in: NEET 2005