When a vibrating tuning fork is placed on a sound box of a sonometer, 8 beats per second are heard when the length of the sonometer wire is kept at $101 \mathrm{~cm}$ or $100 \mathrm{~cm}$. Then the frequency of the tuning fork is (Consider that the tension in the wire is kept constant)

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Aicharya · Accepted Answer

We have, $n l=$ constant $\begin{aligned} n_1 l_1 & =n_2 l_2 \ (n+8) 100 & =(n-8) 101 \ \frac{n+8}{n-8} & =\frac{101}{100} \ \frac{n}{8} & =\frac{201}{1} \ n & =1608\end{aligned}$

When a vibrating tuning fork is placed on a sound box of a sonometer, 8 beats per second are heard when the…

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