When a system is taken from state ' $a$ ' to state ' c ' along a path abc , it is found that $\mathrm{Q}=80…
When a system is taken from state ' $a$ ' to state ' c ' along a path abc , it is found that $\mathrm{Q}=80 \mathrm{cal}$ and $\mathrm{W}=35 \mathrm{cal}$. Along path adc, $\mathrm{Q}=65 \mathrm{cal}$ the work done W along path adc is
20 cal .
45 cal .
35 cal .
65 cal .
Solution
For both the paths, $\Delta \mathrm{U}$ remains same.
For path abc: $\Delta \mathrm{U}=\mathrm{Q}-\mathrm{W}=80-35=45 \mathrm{cal}$ For path adc : $\Delta U=45 \mathrm{cal}$ and $Q=65 \mathrm{cal}$ $\mathrm{W}=\mathrm{Q}-\Delta \mathrm{U}=65-45=20 \mathrm{cal}$
