When a string of length ' $l$ ' is divided into three segments of length $l_1, l_2$ and $l_3$. The…
When a string of length ' $l$ ' is divided into three segments of length $l_1, l_2$ and $l_3$. The fundamental frequencies of three segments are $\mathrm{n}_1, \mathrm{n}_2$ and $\mathrm{n}_3$ respectively. The original fundamental frequency ' $n$ ' of the string is
The fundamental frequency of a string is given by
Given: $l=l_1+l_2+l_3$... (i)
$\mathrm{n}=\frac{1}{2 l} \sqrt{\frac{\mathrm{T}}{\mathrm{m}}}$
$\Rightarrow \mathrm{n} \propto \frac{1}{l}$ or $\mathrm{n} l=\mathrm{k}$
$\therefore \quad l_1=\frac{\mathrm{k}}{\mathrm{n}_1}, l_2=\frac{\mathrm{k}}{\mathrm{n}_2}$ and $l_3=\frac{\mathrm{k}}{\mathrm{n} 3}$... (ii)
$\therefore \quad$ Original length $l=\frac{\mathrm{k}}{\mathrm{n}}$... (iii)
Putting eq (ii) and (iii) into eq (i)
$\frac{\mathrm{k}}{\mathrm{n}}=\frac{\mathrm{k}}{\mathrm{n}_1}+\frac{\mathrm{k}}{\mathrm{n}_2}+\frac{\mathrm{k}}{\mathrm{n}_3}$
$\therefore \quad \frac{1}{n}=\frac{1}{n_1}+\frac{1}{n_2}+\frac{1}{n_3}$