When a sound wave of wavelength $\lambda$ is propagating in a medium, the maximum velocity of the particle is equal to the wave velocity. The amplitude of wave is

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Aicharya · Accepted Answer

$\begin{aligned} & v_{\max }=v \ & \Rightarrow \quad A \omega=v \ & \Rightarrow \quad A 	imes 2 \pi v=v \lambda \ & A=\frac{\lambda}{2 \pi} \ & \end{aligned}$

When a sound wave of wavelength $\lambda$ is propagating in a medium, the maximum velocity of the particle…

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