When a pure resistor is connected to an AC source, the phase difference between the voltage and the current…
When a pure resistor is connected to an AC source, the phase difference between the voltage and the current through the resistor is
- \(90^{\circ}\)
- \(180^{\circ}\)
- \(45^{\circ}\)
- \(0^{\circ}\)
Solution
In purely resistive circuit, alternating voltage and alternating current, both are in same phase, hence phase difference is zero.
Asked in: AP EAMCET 2020 (18 Sep Shift 2)
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