When a potential difference V is applied across a wire of resistance R , it dissipates energy at a rate W .…

When a potential difference V is applied across a wire of resistance R, it dissipates energy at a rate W. If the wire is cut into two halves and these halves are connected mutually parallel across the same supply, the energy dissipation rate will become:
  1. 14 W
  2. 12 W
  3. 2 W
  4. 4 W

Solution

For first case:

V2R=W     ...(i)

Now, equivalent resistance of the combination will be R2×R2R2+R2=R4

For second case:

W'=V2R4    ...(ii)

From (i) & (ii), we get
W'=4 W

Asked in: JEE Main 2024 (30 Jan Shift 2)

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