When a liquid of density ' $\rho$ ' flows through a tube of diameter ' $d$ ' with critical velocity '…

When a liquid of density ' $\rho$ ' flows through a tube of diameter ' $d$ ' with critical velocity ' $\mathrm{V}$ ' then the Reynolds number is $\text { ( } \eta=\text { coefficient of viscosity of liquid) }$
  1. $\frac{\eta \rho}{V d}$
  2. $\frac{\mathrm{Vd}}{\rho \eta}$
  3. $\frac{\mathrm{Vpd}}{\eta}$
  4. $\frac{V \eta d}{\eta}$

Solution

Dimensionless number that helps to find the dominant force between inertial force and viscous force. It is defined as, $\text { Reynold's number }=\frac{\text { inertial force }}{\text { viscous force }}=\left(\frac{\rho \mathrm{Vd}}{\eta}\right)$

Asked in: MHT CET 2022 (08 Aug Shift 2)

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