When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in the…

When a diploid female plant is crossed with a tetraploid male, the ploidy of endosperm cells in the resulting seed is:
  1. tetraploidy
  2. pentaploidy
  3. diploidy
  4. triploidy.

Solution

Female parent genotype $=2 \mathrm{~N}=2 \mathrm{~A}$ Male Gamete formed $=\mathrm{N}=\mathrm{A}$ Male parent genotype $=2 \mathrm{~N}=4 \mathrm{~A}$ Male Gamete formed $=\mathrm{N}=2 \mathrm{~A}$ Endosperm is formed by the fusion of 2 polar nuclei (from female gamete) and 1 male gamete. Thus, the ploidy of endosperm $=$ $3 \mathrm{~N}=\mathrm{A}+\mathrm{A}+2 \mathrm{~A}=4 \mathrm{~A}$ (tetraploid)

Asked in: NEET 2004

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