When a current of $1 \mathrm{~A}$ is passed through a coil of 100 turns, the flux associated with it is $2.5…

When a current of $1 \mathrm{~A}$ is passed through a coil of 100 turns, the flux associated with it is $2.5 \times 10^{-5} \mathrm{~Wb} /$ turn. The self inductance of the coil in millihenry is
  1. $40$
  2. $25$
  3. $4$
  4. $2.5$

Solution

Given: $N=100, I=1 \mathrm{~A}$, $\phi=2.5 \times 10^{-5} \mathrm{~Wb} /$ turn Self-inductance of coil, $\begin{aligned} \mathrm{L} & =\frac{\mathrm{N} \phi}{\mathrm{I}} \\ \therefore \quad \mathrm{L} & =\frac{100 \times 2.5 \times 10^{-5}}{1}=2.5 \times 10^{-3} \mathrm{H}=2.5 \mathrm{mH} \end{aligned}$ .

Asked in: MHT CET 2023 (11 May Shift 1)

Practice more Electromagnetic Induction questions on Aicharya