When a current $I$ flows through a coil, it stores the energy $E_1$ in it. Now the current is reduced to…

When a current $I$ flows through a coil, it stores the energy $E_1$ in it. Now the current is reduced to $\frac{l}{2}$, the energy stored in the coil becomes $E_2$. The change in the energy is
  1. $\frac{E_1}{4}$
  2. $\frac{3 E_1}{4}$
  3. $\frac{4 E_1}{3}$
  4. $\frac{E_1}{2}$

Solution

Energy stored in the coil $E \propto I^2$ $\therefore E_1 \propto I^2 \text { and } E_2 \propto\left(\frac{I}{2}\right)^2$ On taking the ratio: $E_1=4 E_2$ The change in energy is $E_1-E_2=E_1-\frac{E_1}{4}=\frac{3 E_1}{4}$ *

Asked in: MHT CET 2022 (08 Aug Shift 1)

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