When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is :
(Given molar mass in $\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14$, $\mathrm{O}: 16, \mathrm{~S}: 32)$

Question

Aicharya · Accepted Answer

0.1 mole of red-azo dye $($ Molar Mass $=327 \mathrm{gm} / \mathrm{mol})$ will have 32.7 gm mass. Nearly 33 gm.

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K)…

Solution