When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν , the…

When a certain photosensitive surface is illuminated with a monochromatic light of frequency ν, the stopping potential of the photo current is  -V02.  When the surface is illuminated by monochromatic light of frequency ν2, the stopping potential is -V0. The threshold frequency for photoelectric emission is
  1. 5v3
  2. 3v2
  3. 43v
  4. 2v

Solution

hν​=W+V02e

hν​2=W+V0e

On solving, we get, W=32h ν​

⇒hν​0=32h ν​

⇒ν​0=32ν​

Asked in: JEE Main 2019 (12 Jan Shift 2)

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