When a capillary tube is immersed in water vertically, water rises to a height ' $\mathrm{h}^{\prime}$…

When a capillary tube is immersed in water vertically, water rises to a height ' $\mathrm{h}^{\prime}$ inside the tube. If the radius of another capillary tube is $\frac{1}{3}$ that of the previous, the height to which water will rise in this tube, is
  1. $\mathrm{h}$.
  2. $\mathrm{h} \sqrt{3}$
  3. $\frac{\mathrm{h}}{3} .$
  4. 3h.

Solution

$h_{1} r_{1}=h_{2} r_{2}$ $h_{2}=\frac{h_{1} r_{1}}{r_{2}}=3 h$ *

Asked in: MHT CET 2020 (20 Oct Shift 1)

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