When a body slides down on inclined plane with coefficient of friction \(\mu\), then its acceleration will be
- \(g(\sin \theta-\mu \cos \theta)\)
- \(g(\sin \theta+\mu \cos \theta)\)
- \(g(\mu \sin \theta-\cos \theta)\)
- \(g \mu(\sin \theta-\cos \theta)\)
Solution

According to Newton's second law of motion, \(\begin{aligned} \Rightarrow & & m a & =m g \sin \theta-\mu R \\ \Rightarrow & & m a & =m g \sin \theta-\mu m g \cos \theta \\ \Rightarrow & & a & =g \sin \theta-\mu g \cos \theta \\ \Rightarrow & & a & =g(\sin \theta-\mu \cos \theta) \end{aligned}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 1)