When a battery is connected to the two ends of a diagonal of a square conductor frame of side ' $a$ ', the…

When a battery is connected to the two ends of a diagonal of a square conductor frame of side ' $a$ ', the magnitude of magnetic field at the center will be ( $\mu_0=$ permeability of free space)
  1. $\frac{\mu_0}{\sqrt{2} \pi \mathrm{a}}$
  2. $\frac{\sqrt{2} \mu_0}{\pi \mathrm{a}}$
  3. $\frac{\mu_0}{\pi \mathrm{a}}$
  4. Zero

Solution

As shown in the figure, the currents in the parallel sides will produce equal and opposite fields at the center and hence the net magnetic fields at the center will be zero. .

Asked in: MHT CET 2021 (22 Sep Shift 1)

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