When \(30 \mathrm{~mL}\) of \(\mathrm{H}_2\) reacts with \(20 \mathrm{~mL}\) of \(\mathrm{O}_2\) to form…

When \(30 \mathrm{~mL}\) of \(\mathrm{H}_2\) reacts with \(20 \mathrm{~mL}\) of \(\mathrm{O}_2\) to form water, what is leftover when the reaction ends?
  1. \(10 \mathrm{mLH}_2\)
  2. \(5 \mathrm{mLH}_2\)
  3. \(10 \mathrm{mLO}_2\)
  4. \(5 \mathrm{mLO}_2\)

Solution

Given
Here, \(\mathrm{H}_2\) is the limiting reagent. So, \(30 \mathrm{~mL} \mathrm{H}_2\) consumes \(15 \mathrm{~mL}\) of \(\mathrm{O}_2\) as \(\mathrm{H}_2\) and \(\mathrm{O}_2\) react in \(2: 1\) volume ratio (at constant pressure and temperature).

Asked in: AP EAMCET 2020 (18 Sep Shift 2)

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