When 22.4 litres of H 2 g is mixed with 11.2 litres of C l 2 g , each at STP, the moles of H C l g formed is…

When 22.4 litres of H2g is mixed with 11.2 litres of Cl2g, each at STP, the moles of HClg formed is equal to
  1. 1 mol of HClg
  2. 2 mol of HClg
  3. 0.5 mol HClg
  4. 1.5 mol of HClg

Solution

H222.4 lt+Cl211.2 lt2HCl
1 mole=12mole
Limiting reagent is Cl2. So, 1 mole HCl is formed.

Asked in: NEET 2014

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