When \(10 \mathrm{~g}\) of copper and \(10 \mathrm{~g}\) of iodine are mixed, calculate the theoretical…
When \(10 \mathrm{~g}\) of copper and \(10 \mathrm{~g}\) of iodine are mixed, calculate the theoretical yield of CuI according to the equation,
\(2 \mathrm{Cu}+\mathrm{I}_2 \longrightarrow 2 \mathrm{Cul}\)
\(30 \mathrm{~g}\)
\(10 \mathrm{~g}\)
\(15 \mathrm{~g}\)
\(20 \mathrm{~g}\)
Solution
\(\mathrm{I}_2\) is limiting reagent, mole of \(\mathrm{I}_2=\) mole of \(\mathrm{CuI}\)
Mole of \(\mathrm{CuI}=\frac{10}{127}\)
Mass of \(\mathrm{CuI}=\frac{10}{127} \times 190.5=15 \mathrm{~g}\)
Hence, the correct option is (c).