When 1 -chloro butane is treated with aqueous KOH it gives P . However, when it is treated with alcoholic…

When 1-chloro butane is treated with aqueous KOH it gives P. However, when it is treated with alcoholic KOH it gives Q. Identify the products P and Q respectively

Solution

In presence of aqueous KOH, 1-chlorobutane undergoes nucleophilic substitution(SN2 mechansim) to from butan-1-ol

​​​​​​​

Alcoholic KOH dissociates in water to give RO- ion which is a strong base. It abstracts hydrogen, giving rise to elimination in reaction. 

Hence in the presence of alcoholic KOH, dehydro halogenation(beta elimination) takes place  to form but-1-ene, where the cabocation intermediate is formed.

 

Asked in: AP EAMCET 2022 (04 Jul Shift 1)

Practice more Halogen Derivatives questions on Aicharya