When 1 ,   2 - dibromoethane reacts with sodamide giving a product X . The hybridisation state of the…
When dibromoethane reacts with sodamide giving a product . The hybridisation state of the carbons present in it respectively, are
Solution
Alkyl halides react with sodamide in an elimination to yield an alkene or alkyne (from dihalides). For instance,
\(\underset{\text{1, 2-dibromo ethane}}{\mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2-\mathrm{Br}} \xrightarrow[\Delta]{\text { Sodamide }} \stackrel{\mathrm{sp}}{\mathrm{CH}} \equiv \underset{\text{acetylene}}{\stackrel{\mathrm{sp}}{\mathrm{CH}}}\)
Hence, product has both sp-hybridised carbon.