When 0.1 m o l M n O 4 2 - is oxidized the quantity of electricity required to completely M n O 4 2 - to M n…

When 0.1 mol MnO42- is oxidized the quantity of electricity required to completely MnO42- to MnO4- is
  1. 96500 C
  2. 2×96500 C
  3. 9650 C
  4. 96.50 C

Solution

MnO42-→MnO4-
0.1  mole
v.f.=1
So, 0.1 mole=96500×0.1
=9650 C charge is required

Asked in: NEET 2014

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