What will be the volume of oxygen gas produced, If the reaction $2 \mathrm{KClO}_{3(\mathrm{~s})}…
What will be the volume of oxygen gas produced, If the reaction $2 \mathrm{KClO}_{3(\mathrm{~s})} \longrightarrow 2 \mathrm{KCl}_{(\mathrm{s})}+3 \mathrm{O}_{2(\mathrm{~g})} \Delta \mathrm{H}^{\circ}=-78 \mathrm{k} \mathrm{J}$
is carried out at S.T.P.?
48.0 L
44.8 L
22.4 L
67.2 L
Solution
$2 \mathrm{KClO}_{3(s)} \longrightarrow 2 \mathrm{KCl}_{(s)}+3 \mathrm{O}_{2(g)}$
At STP, 1 mole of $\mathrm{O}_{2}=22.4 \mathrm{~L}$
$\therefore 3$ mole of $\mathrm{O}_{2}=22.4 \times 3=67.2 \mathrm{~L}$