What quantity of carbon dioxide is produced when 2 mole of carbon is burnt in $16 \mathrm{~g}$ of dioxygen?
What quantity of carbon dioxide is produced when 2 mole of carbon is burnt in $16 \mathrm{~g}$ of dioxygen?
- $44 \mathrm{~g}$
- $88 \mathrm{~g}$
- $11 \mathrm{~g}$
- $22 \mathrm{~g}$
Solution
$\begin{aligned} & \mathrm{C}+\mathrm{O}_2 \rightarrow \mathrm{CO}_2 \\ & 2 \mathrm{~mol} \frac{16}{32}=0.5 \mathrm{~mol} \\ & 0.5 \mathrm{~mol}(\mathrm{LR}) \\ & \text { Mass of } \mathrm{CO}_2 \text { produced is }=0.5 \times 44=22 \mathrm{~g}\end{aligned}$
Asked in: MHT CET 2022 (06 Aug Shift 2)
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