What is value of spin only magnetic moment of $\mathrm{Ni}(\mathrm{Z}=28)$ in +2 oxidation state?
- $3.1 \mathrm{BM}$
- $0.0 \mathrm{BM}$
- $2.8 \mathrm{BM}$
- $1.7 \mathrm{BM}$
Solution

\(\begin{aligned} & \mathrm{n}=\text { no. of unpaired electrons }=2 \\ & \text {Spin only magnetic moment }=\sqrt{\mathrm{n}(\mathrm{n}+2)} \\ & =\sqrt{2(2+2)} \\ & =8^{0.5} \\ & =2.8 \mathrm{BM}\end{aligned}\)
Asked in: MHT CET 2021 (24 Sep Shift 1)