What is the work done when a gas is compressed from $2.5 \times$ $10^{-2} \mathrm{~m}^3$ to $1.3 \times…

What is the work done when a gas is compressed from $2.5 \times$ $10^{-2} \mathrm{~m}^3$ to $1.3 \times 10^{-2} \mathrm{~m}^3$ at constant external pressure of 4.05 bar?
  1. $4050 \mathrm{~J}$
  2. $4400 \mathrm{~J}$
  3. $4200 \mathrm{~J}$
  4. $4860 \mathrm{~J}$

Solution

$\begin{aligned} & \mathrm{W}=-\operatorname{Pext}\left[\mathrm{V}_2-\mathrm{V}_1\right] \\ & =-4.05\left[1.3 \times 10^{-2}-2.5 \times 10^{-2}\right] \\ & =4.05 \times 1.2 \times 10^{-2}=4.86 \times 10^{-2} \mathrm{bar}-\mathrm{m}^3 \\ & \left(1 \mathrm{bar}=10^5 \mathrm{~Pa}, 1 \mathrm{~Pa}-\mathrm{m}^3=1 \mathrm{~J}\right) \\ & \mathrm{W}=4.86 \times 10^{-2} \times 10^5 \mathrm{~Pa}-\mathrm{m}^2 \\ & =4860 \mathrm{~J} \end{aligned}$

Asked in: MHT CET 2021 (21 Sep Shift 1)

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