What is the volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P.?

What is the volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P.?
  1. $22.4 \mathrm{dm}^3$
  2. $5.6 \mathrm{dm}^3$
  3. $11.2 \mathrm{dm}^3$
  4. $\quad 7.46 \mathrm{dm}^3$

Solution

$\begin{array}{ll} & \mathrm{CH}_4+2 \mathrm{O}_2 \longrightarrow \mathrm{CO}_2+2 \mathrm{H}_2 \mathrm{O} \\ & 1 \text { mole of } \mathrm{CH}_4 \text { requires }=2 \times 22.4 \mathrm{dm}^3 \text { of } \mathrm{O}_2 \\ \therefore \quad & 0.25 \text { mole of methane requires } \\ = & 2 \times 22.4 \times 0.25=11.2 \mathrm{dm}^3 \text { of } \mathrm{O}_2\end{array}$

Asked in: MHT CET 2024 (10 May Shift 1)

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