What is the volume of a gas at $1.032 \times 10^5 \mathrm{Nm}^{-2}$ if it occupies $1 \mathrm{dm}^3$ of…
What is the volume of a gas at $1.032 \times 10^5 \mathrm{Nm}^{-2}$ if it occupies $1 \mathrm{dm}^3$ of volume at normal temperature and pressure?
- $0.982 \cdot \mathrm{dm}^3$
- $1.3 \mathrm{dm}^3$
- $1.5 \mathrm{dm}^3$
- $1.7 \mathrm{dm}^3$
Solution
$1 \mathrm{Nm}^{-2}=1 \mathrm{~Pa}=0.9869 \times 10^{-5} \mathrm{~atm}$
Normal pressure $=1 \mathrm{~atm}$
$\begin{aligned}
\mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\
\mathrm{~V}_1=\frac{1 \mathrm{~atm} \times 1 \mathrm{dm}^3}{\left(1.032 \times 10^5 \times 0.987 \times 10^{-5}\right) \mathrm{atm}}=0.982 \mathrm{dm}^3
\end{aligned}$
Asked in: MHT CET 2024 (10 May Shift 2)
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