$\Lambda_{\mathrm{ClCH}_{2} \mathrm{COONa}}=224 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g}…

$\Lambda_{\mathrm{ClCH}_{2} \mathrm{COONa}}=224 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
$\Lambda_{\mathrm{NaCl}}=38.2 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
$\Lambda_{\mathrm{HCl}}=203 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
What is the value of $\Lambda_{\mathrm{ClCH}_{2} \mathrm{COOH}}$
  1. $288.5 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
  2. $289.5 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
  3. $388.8 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$
  4. $59.5 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$

Solution

$\mathrm{ClCH}_{2} \mathrm{COONa}+\mathrm{HCl} ightarrow \mathrm{ClCH}_{2} \mathrm{COOH}+\mathrm{NaCl}$
$\Lambda_{\mathrm{CICH}_{2} \mathrm{COONa}}+\Lambda_{\mathrm{HCl}}=\Lambda_{\mathrm{ClCH}_{2} \mathrm{COOH}}+\Lambda_{\mathrm{NaCl}}$
$224+203=\Lambda_{\mathrm{ClCH}_{2} \mathrm{COOH}}+38.2$
$\Lambda_{\mathrm{ClCH}_{2} \mathrm{COOH}}=427-38.2$
$=388.8 \mathrm{ohm}^{-1} \mathrm{~cm}^{2} \mathrm{~g} \mathrm{eq}^{-1}$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

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