What is the total number of tetrahedral voids in 0.6 mole of compound that forms hep structure?

What is the total number of tetrahedral voids in 0.6 mole of compound that forms hep structure?
  1. $3.6132 \times 10^{23}$
  2. $7.2264 \times 10^{23}$
  3. $4.8396 \times 10^{23}$
  4. $5.0331 \times 10^{23}$

Solution

$\begin{aligned} 1 \text { mole of compound }= & 6.023 \times 10^{23} \text { atoms } \\ 0.6 \text { mole of compound } & =6.023 \times 10^{23} \times 0.6 \text { atoms } \\ \therefore \quad \text { No. of tetrahedral voids } & =0.6 \times 6.023 \times 10^{23} \times 2 \\ & =7.2264 \times 10^{23} \text { voids }\end{aligned}$

Asked in: MHT CET 2024 (16 May Shift 2)

Practice more Solid State questions on Aicharya