What is the total number of electrons present in bonding orbitals of $\mathrm{O}_2$ molecule according to molecular orbital theory?

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Aicharya · Accepted Answer

The electronic configuration of $\mathrm{O}_2$ molecule is $(\sigma 1 \mathrm{~s})^2\left(\sigma^* 1 \mathrm{~s}\right)^2 \cdot(\sigma 2 \mathrm{~s})^2\left(\sigma^* 2 \mathrm{~s}\right)^2\left(\sigma 2 \mathrm{p}_{\mathrm{z}}\right)^2\left(\pi 2 \mathrm{p}_{\mathrm{x}}\right)^2=$ $\left(\pi 2 p_y\right)^2\left(\pi * 2 p_x\right)^1=\left(\pi^* 2 p_y\right)^1$. Bonding molecular orbitals contain 10 electrons.

What is the total number of electrons present in bonding orbitals of $\mathrm{O}_2$ molecule according to…

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