What is the sum of the interior angles of a pentagon?

What is the sum of the interior angles of a pentagon?
  1. $360^{\circ}$
  2. $540^{\circ}$
  3. $720^{\circ}$
  4. $900^{\circ}$

Solution

Sum $= (n-2) \times 180^{\circ} = (5-2) \times 180^{\circ} = 540^{\circ}$.

Asked in: IMO

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