What is the spin-only magnetic moment value (B.M.) of a divalent metal ion with atomic number 25 , in its…

Electronic configuration of divalent metal ion having atomic number $25$ is

Total number of unpaired electrons$=5$

$\mathrm{\mu }$ (Magnetic moment) $=\sqrt{\mathrm{n}(\mathrm{n}+2)}\mathrm{BM}$

where $\mathrm{n}=$ number of unpaired $\mathrm{e}$

$\therefore \mathrm{\mu }=\sqrt{5(5+2)}=\sqrt{35} \mathrm{B}.\mathrm{M}.=5.92 \mathrm{B}.\mathrm{M}.$