What is the smallest possible atomic number of an element "X" so that the 4 th orbit around X would fit inside the I Bohr orbit of H atom?

Question

Aicharya · Accepted Answer

$\mathrm{r}_{1}=0.529 Å \quad \mathrm{R}_{4(\mathrm{x})}=\mathrm{R}_{1} \times \frac{\mathrm{n}^{2}}{\mathrm{Z}}$
$\mathrm{R}_{4(\mathrm{x})} \Rightarrow \frac{0.529 \times(4)^{2}}{\mathrm{Z}} ; \quad \mathrm{Z}=16$

What is the smallest possible atomic number of an element "X" so that the 4 th orbit around X would fit…

Solution