What is the remainder when $51 \times 27 \times 35 \times 62 \times 75$ is divided by 100?

What is the remainder when $51 \times 27 \times 35 \times 62 \times 75$ is divided by 100?
  1. 50
  2. 25
  3. 5
  4. 1

Solution

We need the last two digits of the product. $51 \times 27 = 1377$ → last two digits 77. $77 \times 35 = 2695$ → 95. $95 \times 62 = 5890$ → 90. $90 \times 75 = 6750$ → last two digits 50. So the remainder when divided by 100 is 50.

Asked in: CSAT 2020

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