What is the remainder of $2 x^3-5 x^2+7$ when divided with $(x-2)$ ?

Question

Aicharya · Accepted Answer

Using remainder theorem, remainder is $P(x=2)$. So, remainder is, $\begin{aligned} P(x=2) & =2 \times 2^3-5 \times 2^2+7 \ & =16-20+7 \ & =3 \end{aligned}$

What is the remainder of \(2 x^3-5 x^2+7\) when divided with \((x-2)\) ?

Solution