What is the reduction electrode potential (in volts) of copper electrode when $\left[\mathrm{Cu}^{2+}ight]=0.01 \mathrm{M}$ is in a solution at $25^{\circ} \mathrm{C}$ ? $\left(E^{\circ}ight.$ of $\mathrm{Cu}^{2+} / \mathrm{Cu}$ electrode is $\left.+0.34 \mathrm{~V}ight)$

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}=\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^0-\frac{0.059}{2} \log \frac{1}{\left[\mathrm{Cu}^{2+}ight]} \ & \mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}=\mathrm{E}_{\mathrm{Cu}^{2+} / \mathrm{Cu}}^0+\frac{0.0591}{2} \log \left[\mathrm{Cu}^{2+}ight]\end{aligned}$ $\begin{aligned} E_{\text {cell }} & =E_{\text {cell }}^{\circ}+\frac{0.0591}{n} \log \left[M^{+}ight] \ & =0.34+\frac{0.0591}{2} \log [0.01] \ & =0.34-\frac{0.0591}{2} \times 2 \ & =0.2809 \text { volt }\end{aligned}$

What is the reduction electrode potential (in volts) of copper electrode when $\left[\mathrm{Cu}^{2+}ight]=0…

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