What is the reaction occurring at the anode in Down's process for the extraction of sodium?
- $4 \mathrm{OH}^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2+4 e^{-}$
- $\mathrm{Na}^{+}+e^{-} \longrightarrow \mathrm{Na}$
- $2 \mathrm{Cl}^{-} \longrightarrow \mathrm{Cl}_2+2 e^{-}$
- $\mathrm{NaOH} \longrightarrow \mathrm{Na}^{+}+\mathrm{OH}^{-}$
Solution
Asked in: AP EAMCET 2002