What is the ratio of the atomic radius of the \(5^{\text {th }}\) orbit in chlorine atom and \(3^{\text {rd…
What is the ratio of the atomic radius of the \(5^{\text {th }}\) orbit in chlorine atom and \(3^{\text {rd }}\) orbit in Helium atom?
\(153: 50\)
\(50: 153\)
\(153: 100\)
\(100: 153\)
Solution
The atomic radius of an atom is given by the formula \(r_n=52.9 n^2 / Z\) pm, where \(r_n\) is the radius of \(n\)th orbit of an atom and \(Z\) is the atomic number of that atom. The ratio of the atomic radius of the \(5^{\text {th }}\) orbit in chlorine atom and \(3^{\text {rd }}\) orbit in Helium atom is \(25 / 17: 9 / 2=50: 153\).