What is the radius of the fourth orbit of hydrogen atom?
What is the radius of the fourth orbit of hydrogen atom?
- $846.4 \mathrm{pm}$
- $211.6 \mathrm{pm}$
- $476.1 \mathrm{pm}$
- $1322.5 \mathrm{pm}$
Solution
$\mathrm{r}_{\mathrm{n}}=\frac{52.9(\mathrm{n})^2}{\mathrm{Z}} \mathrm{pm}$
For hydrogen, $Z=1$
$r_n=\frac{52.9 \times 4^2}{1}=846.4 \mathrm{pm}$
Asked in: MHT CET 2023 (12 May Shift 2)
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